![]() Now it works, I have shortned the numbers to 999 import mathįor i in range(2, int(math. Step 2: Check for each number if it has any factor between 1 and itself. To print all the prime numbers between the given interval, the user has to follow the following steps: Step 1: Loop through all the elements in the given range. Instead, initiate a list and then assign values. The task is to write the Python program for printing all the prime numbers between the given interval (or range). Also, when using that many number of numbers, I would advise against appending lists. Time_2-time_1 # 0.9901950359344482 secondsįor a 100 thousand numbers, using sieves is more than 12 times faster. Sieve = False #because we wont consider zero and one as primes To get a list of primes you can use ]įor ind in range(3,int(math.sqrt(number))+1): So if you want to check if a number is prime, you can simple use sieve. So if we divide a number by integers till the ceiling of its square root and its still indivisible, that means its a prime. Why so? Because a number can't have two factors both of which are greater than the square root of the number. Additionally, to optimize, we iterate only to the square root of 1 million. We will iterate over every number to one million and mark every multiple of it as False in the sieve list. The idea is that we initially create a list called sieve and assign all values to True which means that we are for now considering all numbers to 1 million(inclusive) as primes. Here's how to get all the primes upto one million. ![]() The easiest way to do this is to use something called as Sieve. ![]()
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